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 Depdendent Variable

 Number of equations to solve: 23456789
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 Dependent Variable

 Number of inequalities to solve: 23456789
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 Solve for:

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# Dividing Polynomials

Example 3 using a 0x as a place holder for a missing term divide the first term of the binomial outside into the first term inside and put the results above the division bar

multiply the x on top by the x + 4 outside and write the product of x( x + 4) under the trinominal multiply EACH term in the new row by −1 to create a subtraction problem combine the terms above the underline and bring down the + 5

Start the process over again with the − 4 x + 5 term and the x + 4 outside divide the first term of the binomial outside into the first term of − 4 x +1 multiply the − 4 on top by the x + 4 outside − 4(x + 4) and write the product under the − 4 x + 5 multiply EACH term in the new row by −1 to create a subtraction problem combine the terms above the underline we are done and have a remainer of 21

the answer is Example 4 divide the first term of the binomial outside into the first term inside and put the results above the division bar

multiply the x on top by the 2x + 3 outside and write the product of 3x(2x + 3) under the trinominal multiply EACH term in the new row by −1 to create a subtraction problem combine the terms above the underline and bring down the − 5

Start the process over again with the 6x − 5 term and the 2x + 3 outside  divide the first term of the binomial outside into the first term of multiply the 3 on top by the 2x + 3 outside 3(2x + 3) and write the product under the 6x −5 multiply EACH term in the new row by −1 to create a subtraction problem combine the terms above the underline we are done and have a remainer of −14

the answer is  divide the 2 outside into the first number inside and put the results over the 9

multiply the 4 on top by the 2 outside and write the product 8 under the 9 multiply the 8 in the new row by −1 to create a subtraction problem combine the terms above the underline and bring down the 7

Start the process over again the answer is 